A baby girl named Amel, or "Hope," was born in Syria this month already bearing a shrapnel wound. Amel's mom, Amira, was nine months pregnant when she and three of her children were hurt when an airstrike (reportedly by government forces) hit near their Aleppo home on Sept. 18. Amira "looked sad and confused" when she arrived at a nearby hospital, a spokesperson tells CNN. "She was surrounded by her three wounded kids, (and) she was bleeding from several parts of her body including her belly."
The doctors decided to deliver the baby via emergency C-section, and found that Amel had a piece of shrapnel embedded in her forehead, having gone through Amira's womb. The Syrian Expatriate Medical Association posted pictures on Facebook of the shrapnel being removed, according to the Irish Independent. "We don't know if the baby girl saved her mother from this shrapnel or the mother saved her baby," a doctor tells CNN, "but we all know that the devilish regime tried to kill them both."